Modify Data

In this exercise, you’ll insert, update, and delete data in the Adventureworks database.

Note: This exercise assumes you have created the sample AdventureWorks database.

Insert data

You use the INSERT statement to insert data into a table.

1. Open a query editor for your AdventureWorks database, and create a new query.

2. In the query editor, enter the following code to create a new table named SalesLT.CallLog, which we’ll use in this exercise.

    CREATE TABLE SalesLT.CallLog
    (
        CallID int IDENTITY PRIMARY KEY NOT NULL,
        CallTime datetime NOT NULL DEFAULT GETDATE(),
        SalesPerson nvarchar(256) NOT NULL,
        CustomerID int NOT NULL REFERENCES SalesLT.Customer(CustomerID),
        PhoneNumber nvarchar(25) NOT NULL,
        Notes nvarchar(max) NULL
    );
   

3. Run the code and create the table. Don’t worry too much about the details of the CREATE TABLE statement - it creates a table with some fields that we’ll use in subsequent tasks to insert, update, and delete data.

4. Create a new query, so you have two query panes, and in the new pane, enter the following code to query the SalesLT.CallLog you just created.

    SELECT * FROM SalesLT.CallLog;
   

5. Run the SELECT query and view the results, which show the columns in the new table but no rows, because the table is empty.

6. Switch back to the query pane containing the CREATE TABLE statement, and replace it with the following INSERT statement to insert a new row into the SalesLT.CallLog table.

    INSERT INTO SalesLT.CallLog
    VALUES
    ('2015-01-01T12:30:00', 'adventure-works\pamela0', 1, '245-555-0173', 'Returning call re: enquiry about delivery');
   

7. Run the query and review the message, which should indicate that 1 row was affected.
8. Switch to the query pane containing the SELECT query and run it. Note that the results contain the row you inserted. The CallID column is an identity column that is automatically incremented (so the first row has the value 1), and the remaining columns contain the values you specified in the INSERT statement

9. Switch back to the query pane containing the INSERT statement, and replace it with the following code to insert another row. This time, the INSERT statement takes advantage of the fact that the table has a default value defined for the CallTime field, and allows NULL values in the Notes field.

    INSERT INTO SalesLT.CallLog
    VALUES
    (DEFAULT, 'adventure-works\david8', 2, '170-555-0127', NULL);
   

10. Run the query and review the message, which should indicate that 1 row was affected.
11. Switch to the query pane containing the SELECT query and run it. Note that the second row has been inserted, with the default value for the CallTime field (the current time when the row was inserted) and NULL for the Notes field.

12. Switch back to the query pane containing the INSERT statement, and replace it with the following code to insert another row. This time, the INSERT statement explicitly lists the columns into which the new values will be inserted. The columns not specified in the statement support either default or NULL values, so they can be omitted.

     INSERT INTO SalesLT.CallLog (SalesPerson, CustomerID, PhoneNumber)
     VALUES
     ('adventure-works\jillian0', 3, '279-555-0130');
    

13. Run the query and review the message, which should indicate that 1 row was affected.
14. Switch to the query pane containing the SELECT query and run it. Note that the third row has been inserted, once again using the default value for the CallTime field and NULL for the Notes field.

15. Switch back to the query pane containing the INSERT statement, and replace it with the following code, which inserts two rows of data into the SalesLT.CallLog table.

     INSERT INTO SalesLT.CallLog
     VALUES
     (DATEADD(mi,-2, GETDATE()), 'adventure-works\jillian0', 4, '710-555-0173', NULL),
     (DEFAULT, 'adventure-works\shu0', 5, '828-555-0186', 'Called to arrange deliver of order 10987');
    

16. Run the query and review the message, which should indicate that 2 rows were affected.
17. Switch to the query pane containing the SELECT query and run it. Note that two new rows have been added to the table.

18. Switch back to the query pane containing the INSERT statement, and replace it with the following code, which inserts the results of a SELECT query into the SalesLT.CallLog table.

     INSERT INTO SalesLT.CallLog (SalesPerson, CustomerID, PhoneNumber, Notes)
     SELECT SalesPerson, CustomerID, Phone, 'Sales promotion call'
     FROM SalesLT.Customer
     WHERE CompanyName = 'Big-Time Bike Store';
    

19. Run the query and review the message, which should indicate that 2 rows were affected.
20. Switch to the query pane containing the SELECT query and run it. Note that two new rows have been added to the table. These are the rows that were retrieved by the SELECT query.

21. Switch back to the query pane containing the INSERT statement, and replace it with the following code, which inserts a row and then uses the SCOPE_IDENTITY function to retrieve the most recent identity value that has been assigned in the database (to any table), and also the IDENT_CURRENT function, which retrieves the latest identity value in the specified table.

     INSERT INTO SalesLT.CallLog (SalesPerson, CustomerID, PhoneNumber)
     VALUES
     ('adventure-works\josé1', 10, '150-555-0127');
    
     SELECT SCOPE_IDENTITY() AS LatestIdentityInDB,
            IDENT_CURRENT('SalesLT.CallLog') AS LatestCallID;
    

22. Run the code and review the results, which should be two numeric values, both the same.
23. Switch to the query pane containing the SELECT query and run it to validate that the new row that has been inserted has a CallID value that matches the identity value returned when you inserted it.

24. Switch back to the query pane containing the INSERT statement, and replace it with the following code, which enables explicit insertion of identity values and inserts a new row with a specified CallID value, before disabling explicit identity insertion again.

     SET IDENTITY_INSERT SalesLT.CallLog ON;
    
     INSERT INTO SalesLT.CallLog (CallID, SalesPerson, CustomerID, PhoneNumber)
     VALUES
     (20, 'adventure-works\josé1', 11, '926-555-0159');
    
     SET IDENTITY_INSERT SalesLT.CallLog OFF;
    

25. Run the code and review the results, which should affect 1 row.
26. Switch to the query pane containing the SELECT query and run it to validate that a new row has been inserted with the specific CallID value you specified in the INSERT statement (9).

Update data

To modify existing rows in a table, use the UPDATE statement.

1. On the query pane containing the INSERT statement, replace the existing code with the following code.

    UPDATE SalesLT.CallLog
    SET Notes = 'No notes'
    WHERE Notes IS NULL;
   

2. Run the UPDATE statement and review the message, which should indicate the number of rows affected.
3. Switch to the query pane containing the SELECT query and run it. Note that the rows that previously had NULL values for the Notes field now contain the text No notes.

4. Switch back to the query pane containing the UPDATE statement, and replace it with the following code, which updates multiple columns.

    UPDATE SalesLT.CallLog
    SET SalesPerson = '', PhoneNumber = ''
   

5. Run the UPDATE statement and note the number of rows affected.
6. Switch to the query pane containing the SELECT query and run it. Note that all rows have been updated to remove the SalesPerson and PhoneNumber fields - this emphasizes the danger of accidentally omitting a WHERE clause in an UPDATE statement.

7. Switch back to the query pane containing the UPDATE statement, and replace it with the following code, which updates the SalesLT.CallLog table based on the results of a SELECT query.

    UPDATE SalesLT.CallLog
    SET SalesPerson = c.SalesPerson, PhoneNumber = c.Phone
    FROM SalesLT.Customer AS c
    WHERE c.CustomerID = SalesLT.CallLog.CustomerID;
   

8. Run the UPDATE statement and note the number of rows affected.
9. Switch to the query pane containing the SELECT query and run it. Note that the table has been updated using the values returned by the SELECT statement.

Delete data

To delete rows in the table, you generally use the DELETE statement; though you can also remove all rows from a table by using the TRUNCATE TABLE statement.

1. On the query pane containing the UPDATE statement, replace the existing code with the following code.

    DELETE FROM SalesLT.CallLog
    WHERE CallTime < DATEADD(dd, -7, GETDATE());
   

2. Run the DELETE statement and review the message, which should indicate the number of rows affected.
3. Switch to the query pane containing the SELECT query and run it. Note that rows with a CallDate older than 7 days have been deleted.

4. Switch back to the query pane containing the DELETE statement, and replace it with the following code, which uses the TRUNCATE TABLE statement to remove all rows in the table.

    TRUNCATE TABLE SalesLT.CallLog;
   

5. Run the TRUNCATE TABLE statement and note the number of rows affected.
6. Switch to the query pane containing the SELECT query and run it. Note that all rows have been deleted from the table.

Challenges

Now it’s your turn to try modifying some data.

Tip: Try to determine the appropriate code for yourself. If you get stuck, suggested answers are provided at the end of this lab.

Challenge 1: Insert products

Each Adventure Works product is stored in the SalesLT.Product table, and each product has a unique ProductID identifier, which is implemented as an identity column in the SalesLT.Product table. Products are organized into categories, which are defined in the SalesLT.ProductCategory table. The products and product category records are related by a common ProductCategoryID identifier, which is an identity column in the SalesLT.ProductCategory table.

1. Insert a product
   • Adventure Works has started selling the following new product. Insert it into the SalesLT.Product table, using default or NULL values for unspecified columns:
     • Name: LED Lights
     • ProductNumber: LT-L123
     • StandardCost: 2.56
     • ListPrice: 12.99
     • ProductCategoryID: 37
     • SellStartDate: Today’s date
   • After you have inserted the product, run a query to determine the ProductID that was generated.
   • Then run a query to view the row for the product in the SalesLT.Product table.
2. Insert a new category with two products
   • Adventure Works is adding a product category for Bells and Horns to its catalog. The parent category for the new category is 4 (Accessories). This new category includes the following two new products:
     • First product:
       • Name: Bicycle Bell
       • ProductNumber: BB-RING
       • StandardCost: 2.47
       • ListPrice: 4.99
       • ProductCategoryID: The ProductCategoryID for the new Bells and Horns category
       • SellStartDate: Today’s date
     • Second product:
       • Name: Bicycle Horn
       • ProductNumber: BB-PARP
       • StandardCost: 1.29
       • ListPrice: 3.75
       • ProductCategoryID: The ProductCategoryID for the new Bells and Horns category
       • SellStartDate: Today’s date
   • Write a query to insert the new product category, and then insert the two new products with the appropriate ProductCategoryID value.
   • After you have inserted the products, query the SalesLT.Product and SalesLT.ProductCategory tables to verify that the data has been inserted.

Challenge 2: Update products

You have inserted data for a product, but the pricing details are not correct. You must now update the records you have previously inserted to reflect the correct pricing. Tip: Review the documentation for UPDATE in the Transact-SQL Language Reference.

1. Update product prices
   • The sales manager at Adventure Works has mandated a 10% price increase for all products in the Bells and Horns category. Update the rows in the SalesLT.Product table for these products to increase their price by 10%.
2. Discontinue products
   • The new LED lights you inserted in the previous challenge are to replace all previous light products. Update the SalesLT.Product table to set the DiscontinuedDate to today’s date for all products in the Lights category (product category ID 37) other than the LED Lights product you inserted previously.

Challenge 3: Delete products

The Bells and Horns category has not been successful, and it must be deleted from the database.

1. Delete a product category and its products
   • Delete the records for the Bells and Horns category and its products. You must ensure that you delete the records from the tables in the correct order to avoid a foreign-key constraint violation.

Challenge Solutions

This section contains suggested solutions for the challenge queries.

Challenge 1

1. Insert a product:

    INSERT INTO SalesLT.Product (Name, ProductNumber, StandardCost, ListPrice, ProductCategoryID, SellStartDate)
    VALUES
    ('LED Lights', 'LT-L123', 2.56, 12.99, 37, GETDATE());
   
    SELECT SCOPE_IDENTITY();
   
    SELECT * FROM SalesLT.Product
    WHERE ProductID = SCOPE_IDENTITY();
   

2. Insert a new category with two products:

    INSERT INTO SalesLT.ProductCategory (ParentProductCategoryID, Name)
    VALUES
    (4, 'Bells and Horns');
   
    INSERT INTO SalesLT.Product (Name, ProductNumber, StandardCost, ListPrice, ProductCategoryID, SellStartDate)
    VALUES
    ('Bicycle Bell', 'BB-RING', 2.47, 4.99, IDENT_CURRENT('SalesLT.ProductCategory'), GETDATE()),
    ('Bicycle Horn', 'BH-PARP', 1.29, 3.75, IDENT_CURRENT('SalesLT.ProductCategory'), GETDATE());
   
    SELECT c.Name As Category, p.Name AS Product
    FROM SalesLT.Product AS p
    JOIN SalesLT.ProductCategory as c
        ON p.ProductCategoryID = c.ProductCategoryID
    WHERE p.ProductCategoryID = IDENT_CURRENT('SalesLT.ProductCategory');
   

Challenge 2

1. Update product prices:

    UPDATE SalesLT.Product
    SET ListPrice = ListPrice * 1.1
    WHERE ProductCategoryID =
        (SELECT ProductCategoryID
         FROM SalesLT.ProductCategory
         WHERE Name = 'Bells and Horns');
   

2. Discontinue products:

    UPDATE SalesLT.Product
    SET DiscontinuedDate = GETDATE()
    WHERE ProductCategoryID = 37
    AND ProductNumber <> 'LT-L123';
   

Challenge 3

1. Delete a product category and its products:

    DELETE FROM SalesLT.Product
    WHERE ProductCategoryID =
        (SELECT ProductCategoryID
         FROM SalesLT.ProductCategory
         WHERE Name = 'Bells and Horns');
   
    DELETE FROM SalesLT.ProductCategory
    WHERE ProductCategoryID =
        (SELECT ProductCategoryID
         FROM SalesLT.ProductCategory
         WHERE Name = 'Bells and Horns');